Seahawks make Wilson top-paid in NFL

Russell Wilson is sticking around with the Seattle Seahawks as the highest paid player in the NFL. Wilson posted a video on Twitter on Tuesday morning saying, “Seattle, we got a deal”. His agent, Mark Rodgers, said the deal is a $140m, four-year extension with the Seahawks. Wilson’s new contract runs through the 2023 season and includes a $65m signing bonus, a no-trade clause and $107m in guaranteed money.

Wilson’s per year average of $35m tops Aaron Rodgers’ average annual salary of $33.5m as part of the $134m extension he signed last year with the Green Bay Packers. 

Wilson’s current $87.6m, four-year deal was signed at the beginning of training camp in 2015 and was set to expire after next season. “Russell’s goal and his hope was that he would continue his career with the Seahawks and continue to bring championships to this town,” Mark Rodgers, said. “He believes there is still unfinished business and he is looking forward to pursuing that without having to worry about contracts and his future.”

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The deal ends the debate about Wilson’s future with the Seahawks, although there seemed to be little doubt he would remain in Seattle for a while. The team held leverage knowing it likely had at least three more seasons with Wilson under center. Even if he played out 2019 under his current deal, Seattle could have used the franchise tag if needed to keep him under contract through 2020 and 2021 at a reasonable price by quarterback standards. But the extension allows Seattle to budget for the future knowing how to work with Wilson’s hefty paycheck in the years ahead and build a contender around the former third-round pick that has developed into a franchise QB.

The 5ft 11in Wilson has shelved the stigma of short quarterbacks being unable to play in the NFL. He’s also been extremely durable, never missing a game while playing through significant knee, ankle and shoulder injuries.

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