The New England Patriots agreed to trade tight end Rob Gronkowski and a seventh-round draft pick to the Tampa Bay Buccaneers on Tuesday in exchange for a fourth-round draft pick, the Buccaneers reported. ESPN’s Adam Schefter first reported the news.
Fox Sports’ Jay Glazer stated that Gronkowski passed his physical with the team.
“Rob has agreed to play for Tampa this season,” Gronkowski’s agent, Drew Rosenhaus, told NFL Network’s Ian Rapoport. “He will honor his current contract at this time.”
Reports suggest that Gronkowski, who has one year left on his contract that will pay him $10 million this year, has been getting his body ready for a return to football, and that reuniting with Tom Brady was important.
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Gronkowski, 30, retired ahead of the 2019 campaign after eight seasons with New England. During his Patriots career, he was a three-time Super Bowl champion, five-time Pro Bowler and four-time first-team All-Pro selection. He caught 521 passes for 7,861 yards and 79 scores, establishing himself in his prime as the game’s best tight end and arguably the most talented player at the position in NFL history.
Injuries were an issue for Gronk, however, as he missed 29 matches in his career and 13 games in his last three seasons alone. After posting double-digit touchdown receptions in five of his first six seasons, he had a total of 14 touchdowns between the 2016-18 campaigns.
And now Gronkowski will be playing football with Brady in Tampa Bay next season. It’s great news for Bucs fans and more tough news for Patriots fans, who have seen the most important player in franchise history sign with a new team this offseason and one of the most popular figures in team history come out of retirement to join him.
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